Saponification (basic hydrolysis) of $C_6H_5-CO-^{18}OCH_3$ will yield. [$^{18}O$ = mass $-18$ isotope of oxygen]

  • A
    $C_6H_5-COO^- + CH_3-^{18}OH$
  • B
    $C_6H_5-CO^{18}O^- + CH_3OH$
  • C
    $C_6H_5-COO^- + CH_3OH$
  • D
    $C_6H_5-C(^{18}O)O^- + CH_3OH$

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Match List-$I$ with List-$II$.
List-$I$:
$(a)$ $\text{Benzene} \xrightarrow[\text{CuCl}]{\text{CO, HCl, Anhyd. AlCl}_3} \text{Benzaldehyde}$
$(b)$ $R-CO-CH_3 + NaOX \rightarrow$
$(c)$ $R-CH_2-OH + R'COOH \xrightarrow{\text{Conc. H}_2\text{SO}_4}$
$(d)$ $R-CH_2COOH \xrightarrow[(ii) H_2O]{(i) X_2/\text{Red P}} R-CH(X)COOH$
List-$II$:
$(i)$ $\text{Hell-Volhard-Zelinsky reaction}$
(ii) $\text{Gattermann-Koch reaction}$
(iii) $\text{Haloform reaction}$
(iv) $\text{Esterification}$
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$CH_3-CH_2-COOH$ $\xrightarrow{PCl_3} I$ $\xrightarrow{C_6H_6/AlCl_3} II$ $\xrightarrow{NH_2-NH_2/\text{base/heat}} III$

Identify the wrong statement from the following.

Arrange the following labelled hydrogens in decreasing order of acidity.

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